Convert calorie (it)/gram/°c to btu (it)/pound/°f

Vice Versa: btu (it)/pound/°f to calorie (it)/gram/°c

Calorie (IT)/Gram/°C

The IT calorie per gram per degree Celsius (cal/(g·°C)) equals 4186.8 J/(kg·K). For water, the specific heat capacity is approximately 1 cal/(g·°C), making it a convenient reference. This unit is used in nutrition science, calorimetry, and older thermodynamic literature.

Btu (IT)/Pound/°F

The British thermal unit per pound per degree Fahrenheit (Btu/(lb·°F)) equals 4186.8 J/(kg·K). Water's specific heat is 1 Btu/(lb·°F), making it a convenient reference unit. It is the standard unit for specific heat capacity in North American mechanical and chemical engineering.

Calorie (IT)/Gram/°C to Btu (IT)/Pound/°F conversion table

Calorie (IT)/Gram/°C	Btu (IT)/Pound/°F	Btu (IT)/Pound/°F	Calorie (IT)/Gram/°C
1	1	1	1
2	2	2	2
3	3	3	3
5	5	5	5
10	10	10	10
20	20	20	20
25	25	25	25
50	50	50	50
100	100	100	100
250	250	250	250
500	500	500	500
1000	1000	1000	1000

How to convert Calorie (IT)/Gram/°C to Btu (IT)/Pound/°F

1 cal/(g·°C) = 1 Btu/(lb·°F). To convert any value, multiply it by 1. For example, 25 cal/(g·°C) = 25 Btu/(lb·°F).

Frequently asked questions

How many Btu/(lb·°F) are there in one cal/(g·°C)?: One cal/(g·°C) is equal to 1 Btu/(lb·°F).
How do you convert Calorie (IT)/Gram/°C to Btu (IT)/Pound/°F?: Multiply the value in Calorie (IT)/Gram/°C by 1 to get the result in Btu (IT)/Pound/°F.
How much is 25 cal/(g·°C) in Btu/(lb·°F)?: 25 cal/(g·°C) is equal to 25 Btu/(lb·°F).
How do you convert Btu (IT)/Pound/°F back to Calorie (IT)/Gram/°C?: Divide by the same factor: multiply the value in Btu (IT)/Pound/°F by 1 to get Calorie (IT)/Gram/°C.