Convert calorie (it)/gram/°c to joule/kilogram/k
Joule/Kilogram/K
The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances.
Calorie (IT)/Gram/°C to Joule/Kilogram/K conversion table
| Calorie (IT)/Gram/°C | Joule/Kilogram/K | Joule/Kilogram/K | Calorie (IT)/Gram/°C |
|---|---|---|---|
| 1 | 4186.8 | 1 | 0.0002388 |
| 2 | 8373.6 | 2 | 0.0004777 |
| 3 | 12560.4 | 3 | 0.0007165 |
| 5 | 20934 | 5 | 0.00119423 |
| 10 | 41868 | 10 | 0.00238846 |
| 20 | 83736 | 20 | 0.00477692 |
| 25 | 104670 | 25 | 0.00597115 |
| 50 | 209340 | 50 | 0.0119423 |
| 100 | 418680 | 100 | 0.0238846 |
| 250 | 1.0467E+06 | 250 | 0.0597115 |
| 500 | 2.0934E+06 | 500 | 0.119423 |
| 1000 | 4.1868E+06 | 1000 | 0.238846 |
How to convert Calorie (IT)/Gram/°C to Joule/Kilogram/K
1 cal/(g·°C) = 4186.8 J/(kg·K). To convert any value, multiply it by 4186.8. For example, 25 cal/(g·°C) = 104670 J/(kg·K).
Frequently asked questions
- How many J/(kg·K) are there in one cal/(g·°C)?
- One cal/(g·°C) is equal to 4186.8 J/(kg·K).
- How do you convert Calorie (IT)/Gram/°C to Joule/Kilogram/K?
- Multiply the value in Calorie (IT)/Gram/°C by 4186.8 to get the result in Joule/Kilogram/K.
- How much is 25 cal/(g·°C) in J/(kg·K)?
- 25 cal/(g·°C) is equal to 104670 J/(kg·K).
- How do you convert Joule/Kilogram/K back to Calorie (IT)/Gram/°C?
- Divide by the same factor: multiply the value in Joule/Kilogram/K by 0.0002388 to get Calorie (IT)/Gram/°C.