Convert joule/kilogram/k to btu (it)/pound/°f

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Joule/Kilogram/K

The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances. 


Btu (IT)/Pound/°F

The British thermal unit per pound per degree Fahrenheit (Btu/(lb·°F)) equals 4186.8 J/(kg·K). Water's specific heat is 1 Btu/(lb·°F), making it a convenient reference unit. It is the standard unit for specific heat capacity in North American mechanical and chemical engineering. 


Joule/Kilogram/K to Btu (IT)/Pound/°F conversion table
Joule/Kilogram/KBtu (IT)/Pound/°FBtu (IT)/Pound/°FJoule/Kilogram/K
10.000238814186.8
20.000477728373.6
30.0007165312560.4
50.00119423520934
100.002388461041868
200.004776922083736
250.0059711525104670
500.011942350209340
1000.0238846100418680
2500.05971152501.0467E+06
5000.1194235002.0934E+06
10000.23884610004.1868E+06
How to convert Joule/Kilogram/K to Btu (IT)/Pound/°F

1 J/(kg·K) = 0.0002388 Btu/(lb·°F). To convert any value, multiply it by 0.0002388. For example, 25 J/(kg·K) = 0.00597115 Btu/(lb·°F).

Frequently asked questions
How many Btu/(lb·°F) are there in one J/(kg·K)?
One J/(kg·K) is equal to 0.0002388 Btu/(lb·°F).
How do you convert Joule/Kilogram/K to Btu (IT)/Pound/°F?
Multiply the value in Joule/Kilogram/K by 0.0002388 to get the result in Btu (IT)/Pound/°F.
How much is 25 J/(kg·K) in Btu/(lb·°F)?
25 J/(kg·K) is equal to 0.00597115 Btu/(lb·°F).
How do you convert Btu (IT)/Pound/°F back to Joule/Kilogram/K?
Divide by the same factor: multiply the value in Btu (IT)/Pound/°F by 4186.8 to get Joule/Kilogram/K.

Most common specific heat capacity unit conversions