Convert joule/kilogram/k to btu (it)/pound/°f
Joule/Kilogram/K
The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances.
Joule/Kilogram/K to Btu (IT)/Pound/°F conversion table
| Joule/Kilogram/K | Btu (IT)/Pound/°F | Btu (IT)/Pound/°F | Joule/Kilogram/K |
|---|---|---|---|
| 1 | 0.0002388 | 1 | 4186.8 |
| 2 | 0.0004777 | 2 | 8373.6 |
| 3 | 0.0007165 | 3 | 12560.4 |
| 5 | 0.00119423 | 5 | 20934 |
| 10 | 0.00238846 | 10 | 41868 |
| 20 | 0.00477692 | 20 | 83736 |
| 25 | 0.00597115 | 25 | 104670 |
| 50 | 0.0119423 | 50 | 209340 |
| 100 | 0.0238846 | 100 | 418680 |
| 250 | 0.0597115 | 250 | 1.0467E+06 |
| 500 | 0.119423 | 500 | 2.0934E+06 |
| 1000 | 0.238846 | 1000 | 4.1868E+06 |
How to convert Joule/Kilogram/K to Btu (IT)/Pound/°F
1 J/(kg·K) = 0.0002388 Btu/(lb·°F). To convert any value, multiply it by 0.0002388. For example, 25 J/(kg·K) = 0.00597115 Btu/(lb·°F).
Frequently asked questions
- How many Btu/(lb·°F) are there in one J/(kg·K)?
- One J/(kg·K) is equal to 0.0002388 Btu/(lb·°F).
- How do you convert Joule/Kilogram/K to Btu (IT)/Pound/°F?
- Multiply the value in Joule/Kilogram/K by 0.0002388 to get the result in Btu (IT)/Pound/°F.
- How much is 25 J/(kg·K) in Btu/(lb·°F)?
- 25 J/(kg·K) is equal to 0.00597115 Btu/(lb·°F).
- How do you convert Btu (IT)/Pound/°F back to Joule/Kilogram/K?
- Divide by the same factor: multiply the value in Btu (IT)/Pound/°F by 4186.8 to get Joule/Kilogram/K.