Convert joule/kilogram/k to calorie (it)/gram/°c

Vice Versa: calorie (it)/gram/°c to joule/kilogram/k

Joule/Kilogram/K

The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances.

Calorie (IT)/Gram/°C

The IT calorie per gram per degree Celsius (cal/(g·°C)) equals 4186.8 J/(kg·K). For water, the specific heat capacity is approximately 1 cal/(g·°C), making it a convenient reference. This unit is used in nutrition science, calorimetry, and older thermodynamic literature.

Joule/Kilogram/K to Calorie (IT)/Gram/°C conversion table

Joule/Kilogram/K	Calorie (IT)/Gram/°C	Calorie (IT)/Gram/°C	Joule/Kilogram/K
1	0.0002388	1	4186.8
2	0.0004777	2	8373.6
3	0.0007165	3	12560.4
5	0.00119423	5	20934
10	0.00238846	10	41868
20	0.00477692	20	83736
25	0.00597115	25	104670
50	0.0119423	50	209340
100	0.0238846	100	418680
250	0.0597115	250	1.0467E+06
500	0.119423	500	2.0934E+06
1000	0.238846	1000	4.1868E+06

How to convert Joule/Kilogram/K to Calorie (IT)/Gram/°C

1 J/(kg·K) = 0.0002388 cal/(g·°C). To convert any value, multiply it by 0.0002388. For example, 25 J/(kg·K) = 0.00597115 cal/(g·°C).

Frequently asked questions

How many cal/(g·°C) are there in one J/(kg·K)?: One J/(kg·K) is equal to 0.0002388 cal/(g·°C).
How do you convert Joule/Kilogram/K to Calorie (IT)/Gram/°C?: Multiply the value in Joule/Kilogram/K by 0.0002388 to get the result in Calorie (IT)/Gram/°C.
How much is 25 J/(kg·K) in cal/(g·°C)?: 25 J/(kg·K) is equal to 0.00597115 cal/(g·°C).
How do you convert Calorie (IT)/Gram/°C back to Joule/Kilogram/K?: Divide by the same factor: multiply the value in Calorie (IT)/Gram/°C by 4186.8 to get Joule/Kilogram/K.