Convert joule/kilogram/k to calorie (th)/gram/°c

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Joule/Kilogram/K

The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances. 


Calorie (th)/Gram/°C

The thermochemical calorie per gram per degree Celsius (cal(th)/(g·°C)) uses the thermochemical calorie (4.184 J) rather than the IT calorie (4.1868 J). It is applied in thermochemistry and precise calorimetric experiments where the thermochemical calorie definition is specified. 


Joule/Kilogram/K to Calorie (th)/Gram/°C conversion table
Joule/Kilogram/KCalorie (th)/Gram/°CCalorie (th)/Gram/°CJoule/Kilogram/K
10.00023914184
20.00047828368
30.000717312552
50.00119503520920
100.002390061041840
200.004780112083680
250.0059751425104600
500.011950350209200
1000.0239006100418400
2500.05975142501.046E+06
5000.1195035002.092E+06
10000.23900610004.184E+06
How to convert Joule/Kilogram/K to Calorie (th)/Gram/°C

1 J/(kg·K) = 0.000239 cal(th)/(g·°C). To convert any value, multiply it by 0.000239. For example, 25 J/(kg·K) = 0.00597514 cal(th)/(g·°C).

Frequently asked questions
How many cal(th)/(g·°C) are there in one J/(kg·K)?
One J/(kg·K) is equal to 0.000239 cal(th)/(g·°C).
How do you convert Joule/Kilogram/K to Calorie (th)/Gram/°C?
Multiply the value in Joule/Kilogram/K by 0.000239 to get the result in Calorie (th)/Gram/°C.
How much is 25 J/(kg·K) in cal(th)/(g·°C)?
25 J/(kg·K) is equal to 0.00597514 cal(th)/(g·°C).
How do you convert Calorie (th)/Gram/°C back to Joule/Kilogram/K?
Divide by the same factor: multiply the value in Calorie (th)/Gram/°C by 4184 to get Joule/Kilogram/K.

Most common specific heat capacity unit conversions