Convert poundal foot to nm
Poundal Foot
The poundal-foot (pdl·ft) is a unit of torque in the foot-pound-second (FPS) absolute system, defined as the torque resulting from a force of one poundal acting at a perpendicular distance of one foot. The poundal itself is the absolute unit of force in the FPS system, equal to the force needed to accelerate one pound-mass at one foot per square second. One pdl·ft equals approximately 0.0421401 newton-meters.
Newton-meter
The newton-metre (also newton metre; symbol N⋅m or N m) is a unit of torque (also called moment) in the SI system. One newton-metre is equal to the torque resulting from a force of one newton applied perpendicularly to the end of a moment arm that is one metre long. The nonstandard notation Nm occurs in some fields.
Poundal Foot to Newton-meter conversion table
| Poundal Foot | Newton-meter | Newton-meter | Poundal Foot |
|---|---|---|---|
| 1 | 0.0421401 | 1 | 23.7304 |
| 2 | 0.0842802 | 2 | 47.4607 |
| 3 | 0.12642 | 3 | 71.1911 |
| 5 | 0.2107 | 5 | 118.652 |
| 10 | 0.421401 | 10 | 237.304 |
| 20 | 0.842802 | 20 | 474.607 |
| 25 | 1.0535 | 25 | 593.259 |
| 50 | 2.107 | 50 | 1186.52 |
| 100 | 4.21401 | 100 | 2373.04 |
| 250 | 10.535 | 250 | 5932.59 |
| 500 | 21.07 | 500 | 11865.2 |
| 1000 | 42.1401 | 1000 | 23730.4 |
How to convert Poundal Foot to Newton-meter
1 pdl*ft = 0.0421401 N*m. To convert any value, multiply it by 0.0421401. For example, 25 pdl*ft = 1.0535 N*m.
Frequently asked questions
- How many N*m are there in one pdl*ft?
- One pdl*ft is equal to 0.0421401 N*m.
- How do you convert Poundal Foot to Newton-meter?
- Multiply the value in Poundal Foot by 0.0421401 to get the result in Newton-meter.
- How much is 25 pdl*ft in N*m?
- 25 pdl*ft is equal to 1.0535 N*m.
- How do you convert Newton-meter back to Poundal Foot?
- Divide by the same factor: multiply the value in Newton-meter by 23.7304 to get Poundal Foot.