Convert btu (it)/pound/°f to kilojoule/kilogram/k
Kilojoule/Kilogram/K
The kilojoule per kilogram per kelvin (kJ/(kg·K)) equals 1000 J/(kg·K) and is dem widely use in thermodynamics textbooks and engineering practice. Water's specific heat is approximately 4.18 kJ/(kg·K). It is the standard unit for expressing heat capacities in most engineering thermodynamics calculations.
Btu (IT)/Pound/°F to Kilojoule/Kilogram/K conversion table
| Btu (IT)/Pound/°F | Kilojoule/Kilogram/K | Kilojoule/Kilogram/K | Btu (IT)/Pound/°F |
|---|---|---|---|
| 1 | 4.1868 | 1 | 0.238846 |
| 2 | 8.3736 | 2 | 0.477692 |
| 3 | 12.5604 | 3 | 0.716538 |
| 5 | 20.934 | 5 | 1.19423 |
| 10 | 41.868 | 10 | 2.38846 |
| 20 | 83.736 | 20 | 4.77692 |
| 25 | 104.67 | 25 | 5.97115 |
| 50 | 209.34 | 50 | 11.9423 |
| 100 | 418.68 | 100 | 23.8846 |
| 250 | 1046.7 | 250 | 59.7115 |
| 500 | 2093.4 | 500 | 119.423 |
| 1000 | 4186.8 | 1000 | 238.846 |
How to convert Btu (IT)/Pound/°F to Kilojoule/Kilogram/K
1 Btu/(lb·°F) = 4.1868 kJ/(kg·K). To convert any value, multiply it by 4.1868. For example, 25 Btu/(lb·°F) = 104.67 kJ/(kg·K).
Frequently asked questions
- How many kJ/(kg·K) are there in one Btu/(lb·°F)?
- One Btu/(lb·°F) is equal to 4.1868 kJ/(kg·K).
- How do you convert Btu (IT)/Pound/°F to Kilojoule/Kilogram/K?
- Multiply the value in Btu (IT)/Pound/°F by 4.1868 to get the result in Kilojoule/Kilogram/K.
- How much is 25 Btu/(lb·°F) in kJ/(kg·K)?
- 25 Btu/(lb·°F) is equal to 104.67 kJ/(kg·K).
- How do you convert Kilojoule/Kilogram/K back to Btu (IT)/Pound/°F?
- Divide by the same factor: multiply the value in Kilojoule/Kilogram/K by 0.238846 to get Btu (IT)/Pound/°F.