Convert calorie (th)/gram/°c to joule/kilogram/k

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Calorie (th)/Gram/°C

The thermochemical calorie per gram per degree Celsius (cal(th)/(g·°C)) uses the thermochemical calorie (4.184 J) rather than the IT calorie (4.1868 J). It is applied in thermochemistry and precise calorimetric experiments where the thermochemical calorie definition is specified. 


Joule/Kilogram/K

The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances. 


Calorie (th)/Gram/°C to Joule/Kilogram/K conversion table
Calorie (th)/Gram/°CJoule/Kilogram/KJoule/Kilogram/KCalorie (th)/Gram/°C
1418410.000239
2836820.000478
31255230.000717
52092050.00119503
1041840100.00239006
2083680200.00478011
25104600250.00597514
50209200500.0119503
1004184001000.0239006
2501.046E+062500.0597514
5002.092E+065000.119503
10004.184E+0610000.239006
How to convert Calorie (th)/Gram/°C to Joule/Kilogram/K

1 cal(th)/(g·°C) = 4184 J/(kg·K). To convert any value, multiply it by 4184. For example, 25 cal(th)/(g·°C) = 104600 J/(kg·K).

Frequently asked questions
How many J/(kg·K) are there in one cal(th)/(g·°C)?
One cal(th)/(g·°C) is equal to 4184 J/(kg·K).
How do you convert Calorie (th)/Gram/°C to Joule/Kilogram/K?
Multiply the value in Calorie (th)/Gram/°C by 4184 to get the result in Joule/Kilogram/K.
How much is 25 cal(th)/(g·°C) in J/(kg·K)?
25 cal(th)/(g·°C) is equal to 104600 J/(kg·K).
How do you convert Joule/Kilogram/K back to Calorie (th)/Gram/°C?
Divide by the same factor: multiply the value in Joule/Kilogram/K by 0.000239 to get Calorie (th)/Gram/°C.

Most common specific heat capacity unit conversions