Convert joule/kilogram/k to btu (th)/pound/°f
Joule/Kilogram/K
The joule per kilogram per kelvin (J/(kg·K)) is the SI unit of specific heat capacity. It represents the amount of energy needed to raise one kilogram of a substance by one kelvin. Water has a specific heat capacity of 4182 J/(kg·K), which is exceptionally high compared to most other common substances.
Btu (th)/Pound/°F
The thermochemical British thermal unit per pound per degree Fahrenheit (Btu(th)/(lb·°F)) uses the thermochemical BTU (1054.35 J). It differs slightly from the IT version and is applied in thermochemical research and precise calorimetry where the thermochemical calorie system is used.
Joule/Kilogram/K to Btu (th)/Pound/°F conversion table
| Joule/Kilogram/K | Btu (th)/Pound/°F | Btu (th)/Pound/°F | Joule/Kilogram/K |
|---|---|---|---|
| 1 | 0.000239 | 1 | 4184 |
| 2 | 0.000478 | 2 | 8368 |
| 3 | 0.000717 | 3 | 12552 |
| 5 | 0.00119503 | 5 | 20920 |
| 10 | 0.00239006 | 10 | 41840 |
| 20 | 0.00478011 | 20 | 83680 |
| 25 | 0.00597514 | 25 | 104600 |
| 50 | 0.0119503 | 50 | 209200 |
| 100 | 0.0239006 | 100 | 418400 |
| 250 | 0.0597514 | 250 | 1.046E+06 |
| 500 | 0.119503 | 500 | 2.092E+06 |
| 1000 | 0.239006 | 1000 | 4.184E+06 |
How to convert Joule/Kilogram/K to Btu (th)/Pound/°F
1 J/(kg·K) = 0.000239 Btu(th)/(lb·°F). To convert any value, multiply it by 0.000239. For example, 25 J/(kg·K) = 0.00597514 Btu(th)/(lb·°F).
Frequently asked questions
- How many Btu(th)/(lb·°F) are there in one J/(kg·K)?
- One J/(kg·K) is equal to 0.000239 Btu(th)/(lb·°F).
- How do you convert Joule/Kilogram/K to Btu (th)/Pound/°F?
- Multiply the value in Joule/Kilogram/K by 0.000239 to get the result in Btu (th)/Pound/°F.
- How much is 25 J/(kg·K) in Btu(th)/(lb·°F)?
- 25 J/(kg·K) is equal to 0.00597514 Btu(th)/(lb·°F).
- How do you convert Btu (th)/Pound/°F back to Joule/Kilogram/K?
- Divide by the same factor: multiply the value in Btu (th)/Pound/°F by 4184 to get Joule/Kilogram/K.